RBTree.opBinaryRight

in operator. Check to see if the given element exists in the container.

Complexity: O(log(n))

struct RBTree(T, alias less = "a < b", bool allowDuplicates = true, ALLOC = ThreadMem, bool NOGC_ = false)
pragma(inline, true) const
bool
opBinaryRight
(
string op
)
if (
op == "in"
)
if (
is(typeof(binaryFun!less(T.init, T.init)))
)

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